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For the case that n = 0 (before the first run of the loop), x(0) = 1.For the first actual case, n = 1. X(1) = x(0)3n = 131 = 3.For the next case, n = 2. X(2) = x(1)3n = 332 = 18.For the next case, n = 3. X(3) = x(2)3n = 1833 = 162.For the next and last case, n = 4. X(4) = 16234 which I'm not computing. The computer value of x(4) is the value of the product loop. If that doesn't help, I could try helping again to rephrase, but I'm not sure what else to add.
I think it would be much better to write it in another language, but here's another way to do the second one (this is on Visual Basic): Dim n as long Dim product as long Product = 1 For n = 1 to 4 Product = product * 2 * n Next n
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