ChaoticNeutralCzech @ ChaoticNeutralCzech @feddit.org

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1 yr. ago

LiFePO4 is still superior to traction lead-acid in pretty much every way: energy density, safety, time and cycle life, internal resistance... Yes, they need a BMS but those are very cheap and lots of batteries have them built-in. In fact, I was unable to find 4-cell packs without a BMS inside so I could put two of them in series and balance the 8S cells with each other using an active BMS of my choice, and ended up ordering individual cells and screwing them together.

Today we mourn, tomorrow we moon. Buy the dip at 11:59 PM.

You wouldn't need nearly as much support if they made a decent job in the first place.

Picture translators add text boxes in another language on top of recognized text. They don't contain such artifacts and can be rendered at any resolution. These artifacts will only appear if output from a picture translator is processed further.

It's most likely upscaled. The pictures have the same artifacts.

The pictures have the same kind of artifacts though. This is AI upscaled at the very least.

For any harmonic, you first need to get a sound source of that frequency such as a tuning fork or speaker. It's best to place the source where you expect an antinode to be. You can try to just pluck the string at that point but that will probably also produce a lots of harmonics you don't want.

For the kth harmonic, there are k antinodes at (2i-1)/(2k) of the string length, where i≤k; i∈ℕ.

Fundamental (A1):

• ½ the string length (fret 12)

2nd harmonic (1 octave up, A2):

• ¾ the string length (fret 4.98)
• ¼ the string length

3rd harmonic (perfect fifth from A2 or approx. E3):

• ⅚ the string length (fret 3.15)
• ½ the string length (fret 12)
• ⅙ the string length

4th harmonic (2 octaves up, A3):

• ⅞ the string length (fret 2.32)
• ⅝ the string length (fret 8.14)
• ⅜ the string length
• ⅛ the string length

8th harmonic (4 octaves up, A4):

• 15/16 the string length (fret 1.12)
• 13/16 the string length (fret 3.59)
• 11/16 the string length (fret 6.49)
• 9/16 the string length (fret 9.96)
• 7/16 the string length
• 5/16 the string length
• 3/16 the string length
• 1/16 the string length

Using fractional frets is cumbersome because they are non-linear. You're probably better off with a tape measure or ruler.

the 12th fret is 1 octave up

Yup. 12 semitones is 1 octave so A2 on the bass guitar's A string. The frequency ratio to A1 is 2:1.

5th is 2 octaves

What? No. That's 5 semitones or 500 cents from A1, which is D2, close to a perfect fourth from A1 (frequency ratio 4:3 or 498 cents).

Two octaves would be 24 semitones or 24 frets (not available on most fretted instruments) for a frequency ratio of 4:1, or A3.

just past the second fret is 3 octaves

No! The 2nd fret is 2 semitones or 200 cents above A1, which is B1, close to a major second from A1 (frequency ratio 9:8 or 196 cents).

3 octaves would be 36 semitones or 3600 cents for a frequency ratio of 8:1, or A4.

As Frozengyro@lemmy.world mentioned, you can have interesting results by using harmonics - tones that are a whole (k) multiple of the base frequency because then the string vibrates in a standing wave forming a series of k+1 nodes (including ends) and k antinodes equally spaced across its length. Such notes are:

Frequencies and relations are exact, closest chromatic (piano) notes other than A are approximate, the deviation is expressed in whole cents (hundreths of semitones). Notes more than 20 cents off the chromatic scale will probably sound off so they are discouraged. You could continue forever but frequencies above that will have a very weak response.

Yes, you will get some resonance on non-integer multiples but way less.

I think that would make a standing wave with a series of nodes/antinodes on the string, and how well it works would strongly depend on where the tuning fork is along the string. This has the potential to be more interesting but it's not as easy. See my other comment for a table at which frequencies a standing wave occurs on the A1 string.

For context, bass guitar strings are tuned 3 octaves lower than that. The frequency of the A string is 55 Hz. You can't even reach 220 Hz using the 12th fret on the highest (G) string. Tuning a bass A string to 8 times the frequency would require increasing its tension almost 3 times 64 times. The guitar body should will not survive such forces but the string will snap long before you reach 110 Hz.

Edit: got the quadratic formula the other way around

You can do the experiment on a non-bass guitar: "shorten" the high E string (330 Hz) by 5 frets to reach close to 440 Hz. It's a chromatic scale and not a perfect fifth (error of +0.02 semitones) but that can be corrected without damage by holding the 5th fret and tuning the string to exactly 440 Hz. This shorter string will then react to the tuning fork as intended.

Kind Mita obviously, the 4th one in the list. Short-haired Mita is a close second.

Body disfiguration, mutation, strange diseases and injuries, missing/extra limbs etc. Junji Ito does that a lot.

The bison are copy-pasted to make them resemble the meme.

Cappy best girl?! We have a major disagreement.

It's quite long for what it seems to be

How many times have only the Jews been listened to in political discussion over the Israel/Palestine territory?

It took me embarassingly long to realize what "{f/ves}" means. Female vest? vessel? vestal?

They can do it right now. Enforcement would be a problem in the US but at least he wouldn't be able to fly to the EU. I think the gigafactory is what's stopping it from going through.

I'm really surprised they haven't shot down any Starlink satellites in their airspace. Unidentified or not, Nazi flying objects are illegal in Germany.