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InitialsDiceBearhttps://github.com/dicebear/dicebearhttps://creativecommons.org/publicdomain/zero/1.0/„Initials” (https://github.com/dicebear/dicebear) by „DiceBear”, licensed under „CC0 1.0” (https://creativecommons.org/publicdomain/zero/1.0/)FO
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8
Comments
992
Joined
2 yr. ago

  •  
        
    SPENGLER
    I have a radical idea... The door swings both ways. We could reverse the particle flow through the gate...
    
    RAY
    How? 
    
    SPENGLER
    ... we'll resize a table in Word 
    
    VENKMAN
    Excuse me, Egon.  You said resizing a table was bad...
    
    RAY
    [with realisation]
    ... resize the table...
    
    VENKMAN 
    You're going to endanger us.  You're going to endanger our client; the nice lady who paid us in advance before she turned into a dog
    
    SPENGLER 
    Not necessarily.  There's definitely a very slim chance we'll survive..
    
    WINSTON
    ...
    
    RAY
    ...
    
    VENKMAN
    I love this plan! I'm excited to be a part of it!  Let's do it! 
    
      
  •  
        
    GOZER
    The choice is made. The Traveller has come.
    
    VENKMAN
    We didn't choose anything?!!  I didn't think of an image, did you?
    
    SPENGLER
    No.
    
    WINSTON
    My mind's a total void!
    
    [They all look at Ray]
    
    RAY
    I couldn't help it! It just popped in
    there!
    
    VENKMAN
    What? What just popped in there?
    
    
      
  • Same way it expands to two: When there are three blue eyes, then each of them guesses they might have brown or something and there could be only two blue on the island, in which case as described those two would have left on the second night.

    I don't think that's right.

    Let's try it out:

    Basic case: 1 brown, 1 blue. Day 1. Guru says I see someone with blue eyes, blue eye person immediately leaves. End

    Next: 2 brown, 2 blue.
    Day 1; Guru speaks. It doesn't help anyone immediately because everyone can see a blue eyed person, so no one leaves first night.
    Day 2; The next night, everyone knows this, that everyone else can see a blue eyed person. Which tells the blue eyed people that their eyes are not brown. (They now know no-one is looking at all brown eyes). So the 2 blue eyed people who now realise their eyes aren't brown leave that night on day 2. The end

    Next case: 3 brown, 3 blue (I'm arbitrarily making brown = blue, I don't think it actually matters).
    Day 1, guru speaks, no-one leaves.
    Day 2 everyone now knows no-one is looking at all brown. So if anyone could see only 1 other person with blue eyes at this point, they would conclude they themselves have blue. I suppose if you were one of the three blue eyed people you wouldn't know if the other blue eyed people were looking at 1 blue or more. No-one leaves that night.
    Day 3 I suppose now everyone can conclude that no-one was looking at only 1 blue, everyone can see at least two blue. So if the other blue eyed people can see 2 blues that means you must have blue eyes. So all blue eyed people leave Day 3?

    Hmm. Maybe I've talked my way round to it. Maybe this keeps going on, each day without departure eliminating anyone seeing that many blue eyes until you get to 100.

    It just seems so utterly counterintuitive that everyone sits there for 99 nights unable to conclude anything?

  • I can't see how this expands from your last case of 2 blue eyes to any more blue eyes?

    When there are two blue eyed people (and you can see one of them) then the guru saying they see a blue eyed person has value because you can wait and see what the only person with blue eyes does. If they do nothing it's because the gurus statement hasn't added anything to them (they already see someone with blue eyes). And this in turn tells you something about what they must see - namely that you have blue eyes.

    But how does this work when there are 3 people with blue eyes?

    There isn't anyone who might see no blue eyes. And you know this, because you see at least 2 sets of blue eyes. When no-one leaves on day 1 it's because they're still not sure, because there's no circumstance where the gurus statement helped anyone determine anything. So nothing happening on day 1 doesn't add any useful info to day 2.

    So the gurus statement doesn't seem to set anything in motion?

  • Interesting. But surely they must have had a plan to recover the station if crew were all incapacitated? With it now being near end of life it doesn't matter as much, but early on when billions had been invested? They surely wouldn't have canned the station in event of a catastrophic air leak?

  • true, and i can't think of a legitimate case where it would have tripped me up. but if someone, a novice perhaps, wrote

     
        
    def some_func(foo, bar=[1, 2, 3]):
        bar.reverse()  # for whatever reason
        print(bar)
    
    some_func('hello')    # output [3,2,1]
    some_func('hello')    # output [1,2,3] 
    
      

    i think they would be within their rights to be surprised that calling this function twice has different results. that's what i was surprised by; it feels like bar would be re initialised each time with a scope of the function but apparenty not

  • The "internal business tool" was a well known industry wide product that I had experience in. I should have known that changing an email address in any environment caused that new email address to be notified. It was my fault yes

  • My first week at a major fund company I was assigned to an internal business tool used by thousands. I noticed all the company email addresses in the sandbox weren't correct, so I ran a script to correct them. Cue a call from C-level to my boss asking why he got a "email changed notification". Followed by another.. And another.. And another...

    I went out to lunch