Trump should be caught up in too many legal battles from all the crimes he's committed to have any time to campaign or be relevant in the election. The fact that he's not is already a massive failure of our political system.
Wouldn't you know it, there's a wikipedia article for that. I personally have used 7digital and bandcamp, but qobuz has been mentioned several times in other comments and hdtracks seems like it might work after you create an account.
They might be the most common because they're the easiest, but there are also still plenty of people actually paying for the games. I'll never be convinced that piracy is an actual threat to making money. Piracy has never been easier, just see /c/piracy@lemmy.dbzer0.com for proof, and yet pretty much all forms of entertainmment are as profitable as ever.
https://www.iso-ne.com/
Looking at my own region of New England, renewables are only at about 8% right now. And that includes burning wood, refuse, and landfill gas as renewable sources.
Given r=f(θ), we are generally not concerned with r′=f′(θ); that describes how fast r changes with respect to θ
You're using the derivative of a polar equation as the basis for what a tangent line is. But as the textbook explains, that doesn't give you a tangent line or describe the slope at that point. I never bothered defining what "tangent" means, but since this seems so important to you why don't you try coming up with a reasonable definition?
I think we fundamentally don't agree on what "tangent" means. You can use
x=f(θ)cosθ, y=f(θ)sinθ to compute dydx
as taken from the textbook, giving you a tangent line in the terms used in polar coordinates. I think your line of reasoning would lead to r=1 in polar coordinates being a line, even though it's a circle with radius 1.
We are interested in the lines tangent a given graph, regardless of whether that graph is produced by rectangular, parametric, or polar equations. In each of these contexts, the slope
of the tangent line is dydx. Given r=f(θ), we are generally not concerned with r′=f′(θ); that describes how fast r changes with respect to θ. Instead, we will use x=f(θ)cosθ, y=f(θ)sinθ to compute dydx.
From the link above. I really don't understand why you seem to think a tangent line in polar coordinates would be a circle.
I may not be good at giving it a number, but I can usually see how far apart two things are.