Flipping a coin two times and reading the result as binary gang. (Don't actually do this, coins aren't as fair)
They're only off by about 1% and the bias depends on which side was up, it's not that bad. I wouldn't expect most inexpensive dice to be substantially fairer than that.
D12 with numbers in triplicate appreciators over here
D100 with 25 of each option lover right here
Honestly I'm sure this is the best solution. I get that a d4 is the obvious choice for something that should have a 1/4 chance of happening but a d8 with 4 numbers twice would be the most appropriate.
The only downside I can see is that a d8 and a d8/4 would be easy to mix up at first glance.
You already have d10 and d100 (d00? What do we call the other one?), so there’s precedent for duplicating shapes.
Honestly you only need a d20 and a d6. D4? Divide by 5. D8? D20/5 x d20/10. D12? D6xd10/2
MATH BABY
You don't even need a special die for this. Just roll a d8 and subtract 4 if it's 5-8. Just like using a d6 as a d3.
Just use a dreidel, ya dingus.
For your health.
This is the way
I've never actually had to roll a d4 on a table. Baldur's Gate handles it for me.
I don't get what this means, roll on top or bottom of what?
There are 2 kinds of D4 dice. The result can be on the bottom or on the top of the "piramid".
d8s with duplicate sides gang
Flipping a coin two times and reading the result as binary gang. (Don't actually do this, coins aren't as fair)
They're only off by about 1% and the bias depends on which side was up, it's not that bad. I wouldn't expect most inexpensive dice to be substantially fairer than that.
D12 with numbers in triplicate appreciators over here
D100 with 25 of each option lover right here
Honestly I'm sure this is the best solution. I get that a d4 is the obvious choice for something that should have a 1/4 chance of happening but a d8 with 4 numbers twice would be the most appropriate.
The only downside I can see is that a d8 and a d8/4 would be easy to mix up at first glance.
You already have d10 and d100 (d00? What do we call the other one?), so there’s precedent for duplicating shapes.
Honestly you only need a d20 and a d6. D4? Divide by 5. D8? D20/5 x d20/10. D12? D6xd10/2
MATH BABY
You don't even need a special die for this. Just roll a d8 and subtract 4 if it's 5-8. Just like using a d6 as a d3.